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Gauss vs. Tesla

There are two ``accepted'' units for the magnetic field $\Vec{B}$: GAUSS [abbreviated G] and TESLA [abbreviated T]. Needless to say, both are named after great ${\cal E}$&${\cal M}$ researchers. The former is handy when describing weak magnetic fields - for instance, the Earth's magnetic field is on the order of 1 G - but the unit that goes best with our selected electrical units (because it is defined in terms of meters and coulombs and seconds) is the TESLA. Fortunately the conversion factor is simple:

\begin{displaymath}\hbox{\rm 1~T $\equiv$ 10,000~G. } \end{displaymath}

The TESLA is also defined in terms of the WEBER [W] (named after guess whom), a conventional unit of magnetic flux. The definition is

\begin{displaymath}\hbox{\rm 1~T $\equiv$ 1~W/m$^2$ ~~~ or ~~~ 1~W = 1~T $\times$ 1~m$^2$ } \end{displaymath}

if you're interested. So referring back to Eq. (8), we have

\begin{displaymath}B \, \hbox{\rm [{\sc tesla}]} \; = \; k_M \;
{I \, \hbox{\rm [A]} \; d\ell \hbox{\rm [m]} \over (r \hbox{\rm [m]})^2 }
\end{displaymath}

which we can rearrange to read

\begin{displaymath}k_M \; = { B \, \hbox{\rm [{\sc tesla}]} \; (r \, \hbox{\rm [m]})^2
\over I \, \hbox{\rm [A]} \; d\ell \, \hbox{\rm [m]} }
\end{displaymath}

so that kM must have dimensions of magnetic flux per unit current per unit length or units of W/A-m. Its value is again determined by experiment:

 \begin{displaymath}k_M %
\; = \; 10^7 \; \hbox{\rm W/A-m}
\end{displaymath} (17.20)

I will leave it as an exercise for the student to plug these coupling constants back into the equations where they appear and show that everything is, though weird, dimensionally consistent.


next up previous
Up: Magnetic Units Previous: Magnetic Units
Jess H. Brewer
1999-01-12